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कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
1. Following number line shows the temperature in degree Celsius (℃) at different places on a particulars day?
(a) Observe this number line and write the temperature of the places marked on it ?
(b) What is the temperature difference between the hottest and the coldest places among the above ?
(c) What is the temperature difference between Lahulspiti and Srinagar ?
(d) Can we say temperature of Srinagar and Shimla taken together is less than the temperature at Shimla? Is it also less than the temperature at Srinagar ?
Answer: (a) By observing the above-given data, we can represent the temperature of cities as follows:
( b ) From the above table, it is clear that:
Hottest place temperature = 22℃
Coolest place temperature = −8℃
Therefore,
Temperature difference = Hottest place temperature – Coolest place temperature
= 22 – (-8)
= 30℃
Hence, Temperature between the hottest and coolest place is 30℃
(c) From the above table, it is clear that:
Temperature of Lahaul Spiti = −8℃
Temperature at Srinagar = −2℃
Therefore,
Temperature difference of both cities = Temperature of Lahulspiti - Temperature of Srinagar
= – 8 – (-2)
= – 8 + 2
= −6℃
Hence, The temperature difference between Lahaul Spiti and Srinagar is −6℃.
(d) From the above table, it is clear that:
Temperature of Srinagar = −2℃ Also,
Temperature of Shimla = 5℃
Therefore,
Temperature of Srinagar and Shimla taken together = – 2 + 5
= 3℃
Since,
3℃ > 5℃
3℃ < Temperature of Shimla
It is clear that temperature of Srinagar and Shimla taken together is less than the temperature of Shimla.
कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
2. In a quiz, positive marks are given for correct answers and negative marks are given for incorrect answers. If Jack’s scores in five successive rounds were 25, - 5, - 10, 15 and 10, what was his total at the end?
Answer: It is given in the question that,
Scores of Jack in 5 successive rounds = 25, -5, -10, 15 and 10
Therefore,
The total score of Jack at the and will be the sum of scores of 5 successive rounds
Therefore,
Total score of jack
= 25 + (−5) + (−10) + 15 + 10
= 25 – 5 – 10 + 15 + 10
= 25 – 15 + 15 + 10
= 25 + 10
= 35
कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
3. At Srinagar, temperature was −5℃ on Monday and then it dropped by 2℃ on Tuesday. What was the temperature of Srinagar on Tuesday? On Wednesday, it rose by 4℃. What was the temperature on this day?
Answer: It is given in the question that, Temperature of Srinagar on Monday = −5℃
∵ The temperature of Srinagar on Tuesday = Temperature of Srinagar on Monday −2℃
= −5 − 2
= −7℃
The temperature of Srinagar on Wednesday = Temperature of Srinagar on Tuesday +4℃
= −7 + 4
= −3℃
Therefore, The temperature of Srinagar on Tuesday and the temperature of Srinagar on Wednesday was −𝟕℃ and −𝟑℃ respectively.
कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
4. A plane is flying at the height of 5000 m above the sea level. At a particular point, it is exactly above a submarine floating 1200 m
below the sea level. What is the vertical distance between them?
Answer: It is given in the question that,
The height of plane = 5000 m Also,
As submarine is below the water,
Depth of submarine = – 1200 m
Therefore,
The distance between plane and submarine = 5000 – (-1200)
= 5000 + 1200
= 6200 m
कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
5. Mohan deposits Rs. 2,000 in his bank account and withdraws Rs. 1,642 form it, the next day. If withdrawal of amount from the
account is represented by a negative integer, then how will you represent the amount deposited? Find the balance in Mohan’s account after the withdrawal ?
Answer: (a) It is given in the question that,
The amount deposited in bank account = Rs 2000 Also,
Amount withdrawn from bank account = Rs 1642
Therefore,
Balance left in account = Amount deposited in bank account + Amount withdrawn from the bank account
= 2000 + (– 1642)
= 2000 – 1642
= 358
Therefore, money left in Mohan’s account after withdrawal is Rs 358.
कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
6. Rita goes 20 km towards east from a point A to the point B. From B, she moves 30 km towards west along the same road. If the distance towards east is represented by a positive integer, then how will you represent the distance travelled towards west? By which integer will you represent her final position from A ?
Answer: (a) We have
Distance towards the east is represented by positive whereas distance towards the west is represented by a negative integer It is given in the question that,
Distance travelled in the east direction = 20 km Also, Distance travelled in west direction = 30 km
Therefore,
Distance travelled from A = 20 + (-30)
= – 10 km
As the distance is negative, so we will represent the distance travelled by Rita from A towards the west direction.
कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
7. In a magic square each row, column and diagonal have the same sum. Check which of the following is a magic square.
Answer: (i) Sum of the rows of the box,
5 – 1 – 4 = 0, -5 – 2 + 7 = 0, 0 + 3 – 3 = 0
Sum of the columns, 5 – 5 + 0 = 0, -5 – 2 + 7 = 0, 0 + 3 – 3 = 0
Sum of the diagonals, 5 – 2 – 3 = 0, 0 – 2 – 4 = -6.
As one of the diagonals does not equal to 0, it is not a magic square.
(ii) Sum of the rows,
1 – 10 + 0 = -9, -4 – 3 – 2 = -9
Sum of the columns, 1 – 4 – 6 = -9, -10 – 3 + 4 = -9, 0 – 2 – 7 = -9
Sum of the diagonals, 1 – 3 – 7 = -9, 0 – 3 – 6 = 9
As the sum of rows, columns and diagonals are equal. This is a magic square.
कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
8. Verify a – (-b)= a + b for the following values of a and b:
(i) a = 21, b = 18
(ii) a = 118, b = 125
(iii) a = 75, b = 84
(iv) a = 28, b = 11
Answer: (i) We have given in the question that,
a = 21
b = 18
We have to prove that:
a – (-b) = 21 – (-18)
= 21 + 18
Also,
a + b = 21 + 18
= 39
Therefore, a – (-b) = a + b Hence verified
Answer: (ii) We have given in the question that,
A = 118
B = 125
We have prove that:
a – (-b) = a + b
Now,
a – (-b) = 118 – (-125)
= 118 + 125
= 243
Also,
a + b = 118 + 125
= 243
Therefore, a – (-b) = a + b Hence, verified
Answer: (iii) We have given in the question that,
a = 75
b = 84
We have to prove that:
a – (-b) = a + b
Now,
a – (-b) = 75 – (-84)
= 75 + 84
= 159
Also,
a + b = 75 + 84
= 159
Therefore, a – (-b) = a + b Hence verified,
Answer: (iv) We have given in the question that,
a = 28
b = 11
We have to prove that:
a – (-b) = a + b
Now,
a – (-b) = 28 – (-11)
= 28 + 11
= 39
Therefore, a – (-b) = a + b Hence, verified
कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
9. Use the sign of >, < or = in the box to make the statements true:
(a) (-8) + (-4) ….. (-8) – (-4)
(b) (-3) + 7 – (19) ….. 15 – 8 + (-9)
(c) 39 + (-24) – (15) ….. 36 + (-52) – (-36)
(d) 39 + (-240 – (15) …..-399 + 159 + 81
Answer: (a) (-8) + (-4) ….. (-8) – (-4)
We have,
(-8) + (-4)
= -12
Also,
(-8) – (-4)
= -8 + 4
= -4
Hence,
-12 < -4
⇒ (-8) + (-4) < (-8) – (-4)
Answer: (b) (-3) + 7 – (19) ….. 15 – 8 + (-9)
We have,
(-3) + 7 – (19)
= -22 + 7
= -15
Also,
15 – 8 + (-9)
= 15 – 8 – 9
= 15 – 17
= -2
Hence,
-15 < -2
⇒ (-3) + 7 – (19) < 15 – 8 + (-9)
Answer: (c) 23 – 41 + 11 …. 23 – 41 – 11
We have,
23 – 41 + 11
= -18 + 11
= - 7
Also,
23 – 41 = 11
= 23 – 52
= - 29
Hence,
-7 > - 29
23 – 41 + 11 > 23 – 41 – 11
Answer: (d) 39 + (-24) – (15) … 36 + (-52) – (-36)
We have,
39 + (-24) – (15)
= 39 – 24 – 15
= 39 – 39
= 0
Also,
36 + (-520 – (-36)
= 36 – 52 + 36
= 72 – 52
= 20
Hence,
0 < 20
39 + (-24) – 15 < 36 + (-52) – (-36)
Answer: (e) -231 + 79 + 51 ….. – 399 + 159 + 81
We have,
- 231 + 79 + 51
= - 231 + 130
= -101
Also,
- 399 + 159 + 81
= -399 + 240
= -159
- 101 > - 159
- 231 + 79 + 51 > - 399 + 159 + 81
कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF video download In English | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 |
10. A water tank has steps inside it. A monkey is sitting on the topmost step (i.e., the first step). The water level is at the ninth step ?
(i) He jumps 3 steps down and then jumps back 2 steps up. In how many jumps will he reach the water level?
(ii) After drinking water, he wants to go back. For this, he jumps 4 steps up and then jumps Back 2 steps down in every move.
In how many jumps will he reach back the top step?
(iii) If the number of steps moved down is represented by negative integers and the number of steps moved up by positive integers, represent his moves in part (i) and (ii) by completing the following: -3 + 2 -.....= -8 ; 4 – 2 + 4 – 2 ....= 8. In (a), the sum (-8) represents going down by eight steps. So, what will the sum 8 in (b) represent?
Answer: (i) Let us assume, down moved steps be represented by positive whereas up moved steps be represented by negative integers.
It is given that, Initially the monkey will be at step = 1
After the 1st jump monkey’s step = 1 + 3 = 4
After the 2nd jump monkey’s step = 4 + (-2) = 2
After the 3rd jump monkey’s step = 2 + 3 = 5
After the 4th jump monkey’s step = 5 + (-2) = 3
After the 5th jump monkey’s step = 3 + 3 = 6
After the 6th jump monkey’s step = 6 + (-2) = 4
After the 7th jump monkey’s step = 4 + 3 = 7
After the 8th jump monkey’s step = 7 + (-2) = 5
After the 9th jump monkey’s step = 5 + 3 = 8
After the 10th jump monkey’s step = 8 + (-2) = 6
After the 11th jump monkey’s step = 6 + 3 = 9
Hence, From above results it is clear that the monkey will be at water level i.e., 9 after 11 jumps.
Answer: (ii) From above, we have Initial step of monkey = 9
Therefore,
After the 1st jump monkey’s step = 9 + (-4) = 5
After the 2nd jump monkey’s step = 5 + 2 = 7
After the 3rd jump monkey’s step = 7 + (-4) = 3
After the 4th jump monkey’s step = 3 + 2 = 5
After the 5th jump monkey’s step = 5 + (-4) = 1
Hence, It is clear from the above results is that after 5 jumps the monkey will reach back at the top
Answer: (iii) If we will represent the down steps by negative and up steps by positive than the moves are as follows: We have,
Moves in
(i): - 3 + 2 – 3 + 2 – 3 + 2 – 3 + 2 – 3 + 2 – 3 = 8
Also, Moves in part
(ii): 4 – 2 + 4 – 2 + 4 = 8
Therefore, Moves in part (ii) shows those steps who moves up.
नए पैटर्न पर आधारित एनसीईआरटी समाधान कक्षा 7वी के अध्याय 1 प्रश्नावली 1.1 के सभी प्रश्नों का हल अंग्रेजी में दिया गया है, यदि समाधान समझ न आए तो कृपया video की सहायता ले 🙏
NCERT New Pattern Maths Class 7th Chapter 1 Integers Exercise 1.1 Solution PDF download In English | ncert solutions for class 7 math chapter 1 exercise 1.1 PDF and Videos in English | math class 7 chapter 1 Integers exercise 1.1 in Hindi and English | एनसीईआरटी समाधान कक्षा 7 गणित अध्याय 1 पूर्णांकों PDF | कक्षा 7 गणित अध्याय 1 पूर्णांक अभ्यास 1.4 समाधान अंग्रेजी और हिंदी में | प्रश्नावली 1.1 कक्षा 7 | Class 7 Maths Chapter 1 Exercise 1.1 Solutions Question 1 to 10 |
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